A tricky sum

If (a-7)2 + (b-5)2 + (c+3)2 = 0

Then find the value of a, b and c.

2 Answers

1
hacker ·

a=7,b=5c=-3

1
Arka Halder ·

we know that square of any number is greater than or equal to 0.
so for the sum of three such squares to be 0,each must be 0 individually.
thus a-7=0;b-5=0;c+3=0
and hence a=7,b=5 and c=-3. [1]

Your Answer

Close [X]