Help me proove this

Prove that √2 is a rational or an irrational

3 Answers

21
Shubhodip ·

Let √2= ab, where gcd(a,b)=1

so 2 = a2b2

or 2b2=a2

so 2|a2 →2|a

and 2|b2→2|b

which contradicts gcd(a,b) = 1

so its irrational;)

36
rahul ·

If possible let √2 be rational

so, √2 = a/b where a and b are integers in the simplest form having no common factors other than 1

=> a2/b2 = 2

=> a2 = 2b2 ----- (i)

Now, 2 divides 2b2 => 2 divides a2

and, since 2 is prime and divides a2 => 2 divides a [result 1]

since, 2 divides a so, let a = 2c, for any integer c

putting, a = 2c in (i) we get,

(2c)2 = 2b2

=> 4c2 = 2b2

=> b2 = 2c2

Now, since 2 divides 2c2 => 2 divides b2

and since 2 is prime and divides b2 => 2 divides b [result 2]

But we get a contradiction from results 1 and 2 that, a and b are integers in the
simplest form having no common factors other than 1.

Hence, √2 is irrational.

Dhanyavad

1
Aravind Kukkila ·

Thanks a lot .

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