in every three consecutive integers there will always be an even no. and the product of any no. with an even no. will give an even no. and so it is divisible by 2
i can't prove why is it divisible by 3 :P
- Srijan Banerjee i have worked out this to 12
the product of every alternate no. is a multiple of 3 hope it helps :)Upvote·0· Reply ·2013-07-13 06:58:12
- Astha Gupta the concept that u presented about divisibility by 2...was nice..but the second thing...that is...about 12...i didn't get it...can u xplain way did u mean..????
- Astha Gupta i mean wat did u mean..n thanks in advance...