Mensuration(class X)

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In the given figure, a chord AB of a circle of 10cm radius subtends a rt. angle at the centre O.Find the area of the sector OABC & of the major segment.(pie=3.14)

#Mathematics #Class VII-X Mathematics

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Gone.. ·2009-08-04 00:17:10

ar OABC= Ï€R²/4.
R=10(given)

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Devil ·2009-08-04 01:33:18

Area = Î¸360. Ï€r²...here Î¸=90 deg....

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rahul1993 Duggal ·2009-08-04 02:47:41

let radius=r
we have 10²=2r² (from pythagorus theorem)
or r=âˆš50
area of circle = 3.14(50)=15.7
area of shaded region= 15.7 / 4
=3.925 cm²

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rahul ·2011-02-04 00:04:39

Area of the shaded sector = Î¸/360 x âˆ© r²
= 90/360 x (3.14) x 25 = 1/4 x 78.5 = 19.63 cm²

Area of the major sector = area of the circle - area of the minor sector
= 22/6 x 25 - 19.63 = 91.67 - 19.63 =72.04 cm²

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oishitmitra ·2011-08-23 06:08:41

kamon!! dis was toooo easy!!

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Mensuration(class X)

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