1IN ABC,M is the mid point of AB and DM is parellel to CB.
|ADM=|MDC=90
by converse of midpoint theorem,AD=DC
in ADM and CDM are congruent by SAS.AM=MC
hence,AM=MC=MB
ABC IS A TRIANGLE RIGHT ANGLED AT C , A LINE THROUGH THE MID POINT M OF HYPOTENUSE AB AND PARALLEL TO BC INTERSECT AC AT D SHOW THAT-
(a)D IS THE MID POINT OF AC
(b)MD IS PERPENDICULAR ON AC
(c)CM = MA = 1/2AB
HEP SOLVING IT!AND PLZ STATE THE REASONS WERE NECESSARY.
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