AIEEE

1) If \alpha, \beta, \gamma and \delta are the angles made by a line with the diagonals of a cube, then cos^2\alpha +cos^2\beta +cos^2\gamma +cos^2\delta is equal to :

(a) 0
(b) 1
(c) 2/3
(d) 4/3

14 Answers

1
playpower94 ·

option d >> 4/3

11
Anirudh Narayanan ·

2) The sum of distances of (1,-1,-1) from the axes is

(a) 3√2
(b) 2√3
(c) √3
(d) √6

I think the answer is 3......problem is, it is not among the options [2]

62
Lokesh Verma ·

it is a) 3√2

Think again :)

1
JOHNCENA IS BACK ·

yups 3 root 2.think three dimensionally.

11
Anirudh Narayanan ·

bhaiya, (1,-1,-1) is at a distance of 1 from each axis....so sum of distances is 3, right?

11
Anirudh Narayanan ·

oooooooooooooops sorry

got it now

thanx bhaiya and john

62
Lokesh Verma ·

Think again! what is the distance of th epoint (1,1,1) from line x axis?

62
Lokesh Verma ·

ok great you got it :)

1
Ritika ·

Maybe u got confused by drawin it 2 dimensionally. Try imaginin it it 3D. The distances of the point from 2 of the axes won't be 1 unit.

1
Ritika ·

ok...nd 4 my part, i should improve ma WPM.

11
Anirudh Narayanan ·

3) The equation of the line x-y+2z=5, 3x+y+z=6 in symmetrical form is?

4) The equation of the plane passing through the intersection of the planes z-2y+z+4=0 and 4x+y+2z+1=0 is?

5) The shortest distance of the point (2,-4,4) from the plane r.(3i-j+4k)=0 is

(a)7
(b)√21
(c)2√21
(d) 1

11
Anirudh Narayanan ·

Anyone cares to answer?

1
Philip Calvert ·

3rd wud be a bit lengthy sort i mean im feeling too lazy to do it now

4th well there can be many many planes passing thru their line of intersection

in fact there will be a family of planes given by P1 + k P2 =0
which should represent diffnt planes for diffnt k (except P2 that is)

and please check the eqn of the 1st plane is it x-2y ??

1
Philip Calvert ·

according to me in 5th question (im not 100 percnt sure )

the equation is same as 3x -y + 4z =0
now we can solve it

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