1@surbhi please respond yaar
A circle of radius 5 units has diameter along the angle bisector of the lines x+y = 2 and x - y = 2. If chord of contact from origin makes an angle of 45° with the positive direction of x axis then the equation of the circle is given by
1. (x-2)2 + (y-2)2 = 25
2. (x+2)2 + (y+2)2 = 25
3. (x-2)2 + (y+2)2 = 25
4. none of these
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5 Answers
24its easy..
eqn of angle bisector b/w these lines is..
\frac {x+y-2}{\sqrt {2}}=\pm \frac {x-y-2}{\sqrt {2}}
and eqn of chord of contact to our circle x^2+y^2+2gx+2fy+c=0 \ is \ xx_1+yy_1+g(x+x_1)+f(y+y_1)+c=0 with Slope=1
Also it is known that g^2+f^2-c=25
Use all of them to get ans