CONIC

MULTIPLE OPTIONS CORRECT

The equation x2 + 2xy + x - 3 - y + y2 = 0 represents a conic with
(A) eccentricity 1 (B) vertex (1.5,-1.5)
(C) axis as x + y = 0 (D) length of latus rectum 1

9 Answers

13
Двҥїяuρ now in medical c ·

B is wrong.....

11
rkrish ·

@abhirup
Pls check once again.

11
rkrish ·

@abhirup

H2 = AB . Hence,it is a parabola.!!
So, A is correct.

I'm sorry about (1.5,1.5)....I made a mistake..The option is actually (1.5,-1.5)
Also the curve IS symmetrical about x=-y

21
tapanmast Vora ·

MOST CONVINCING METHOD FOR B IS :

PARTIAL DIFFERENTIATE; ONCE WITH Y AND NEXT WID X...

SOLVE SIMULT EQN.... U GET UR VERTEX.....

NOW LENGTH OF LATUS RECTUM NEEDS 2 B CN.....

1
rajat agarwal ·

i am getting all the options to be correct am i right ?

1
skygirl ·

x^2 + 2xy + x - 3 - y + y^2 = 0

==parabola .

(x+y)2 = (y-x+3)

=> Y2 = 4aX [Y=x+y, X=y-x+3]

so, 4a=1 => a=1/4

axis is X-axis i.e. Y=0 => x+y=0

vertex will be the intersection point of x+y=0 and y-x=3.

so, ans-> B and C.

1
skygirl ·

even A is correct. (bad mistake [3])

11
Subash ·

4a=1(length of latus rectum)

so D is correct too isnt it

1
skygirl ·

opsie!

yeah..

i thot they wanted value of a [3]

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