coordinate

the locus of the point of intersection of the lines x/a +y/b = m & x/a - y/b = 1/m , where m is a parameter , is always :
(a)a circle
(b) a parabola
(c) a ellipse
(d) a hyperbola

6 Answers

1
mohit sengar ·

2. the centre and focus of the ellipse ( x+y -2 )2 /9 + ( x-y )2 / 16 = 1 , is

11
Joydoot ghatak ·

will u please check the first sum...

11
Joydoot ghatak ·

for 2) the centre is (1,1).
(x+y-26)296 + (x-y2)2162 = 1

or, X2(36)2 + Y2(√8)2 =1

u can get the centre, X=0 and Y=0
thus we get centre as (1,1).

1
mohit sengar ·

sorry , fr that
now the eq is correct

one more ques ......

the angle between the pair of tangents drawn to the ellipse , 3x2 + 2y2 = 5 , from the point ( 1,2 ) is :

11
Joydoot ghatak ·

1.
by solving, we get

x=a2 [m+1/m]
or, xa= 12 [m+1/m]

and , yb = 12 [m-1/m]

we know,
[m+1/m]2 - [m-1/m]2 = 4.m.1m

or, [m+1/m]2 - [m-1/m]2 = 4.

or, [ 12 (m+1/m) ]2 - [ 12 (m-1/m) ]2 = 1

or, x2a2 - y2b2 = 1.

thus it represents a hyperbola. :)

6
AKHIL ·

@mohit

the last quesn u posted can be easily solved by drawing the fig.

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