1naa actually A and B are points on the same side of the given line !
but problem is that i cant imagine the three points to be collinear !
and dude @bhargav, P is the point on the line ..not A and B !
Consider the points A≡(0,1) and B≡(2,0) .let P be a point on the line 4x+3y+9=0.
coordinates of the point 'P' such that |PA-PB| is maximum, are ?
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19 Answers
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1then ur locus will the path dat p travels...but its already on the line....how did u think dat ur hint will help...i m not getting?
1@nishantbhaiya.com difference between lengths ...which lengths...pa and pb.......????
1i think it should be minimum priyam has correct explained is the ans. correct
33|PA-PB|≤AB
equality holds when PAB are collinear and P is outside AB...
1ONE WAY IS 2 DO IT MAXIMA BY WRITING THE DISTANCE FORMULA AND THEN SUBSTITUTING Y IN TERMS OF X FROM DA GIVEN EQN. OF LINE
62if difference of lengths is a constant then it is a hyperbola..
will this hint help?
11wellll actually i mislooked the question
i was postig the answer for minimum distance
what first conditon
1good magic math rocks ! .try at home ! [4]
subash .....shortcut ?........yar its a simple crap but the first condition is wat that enthrails me a lot [5]
answer is not important
1u'll get the x-cordinate by differentiating the equation and equating to zero....
u can then get both the cordinates of the point 'P'
y did u say wat will u prove???
i dint get u....
hope now u get my point