f(x,y) = x2-y2+2x+4y-12
ok ? .this is the curve or anything ! [4]
NOW,
IF r is the radius of the circle which touches the curve f(x,y)=0, y=x+1 and y=-x+3, then the least possible value of 'r' (in units) approximately is WHAT ?
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1 Answers
62x2-y2+2x+4y-12=0
(x+1)2-(y-2)2=9
Now the shifting of coordinates is the best method that you can use
subs x+1=X
y-2=Y
so we get equations as
X2-Y2=9
Y+2=X
and Y+X=2
Now I think you can do it?
