For a > 0, prove that the circle x2 + y2 =1 and the parabola y=ax2 - b
intersect at four distinct points, provided a>b>1.
This is the solution given in my book.
Since a>0, by figure -b<-1 i.e. b>1
also when y=0
x2=b/a (from the equation of the parabola)
The step which I did not understand is this-
Therefore, b/a <1 i.e.
b<a
Hence a>b>1
Please tell how is b/a <1...is it form figure...or some logic?
-
UP 0 DOWN 0 0 0
