39tangent equation would be yt=x+t2
equation to normal would be √5 tanφx -2y - sinφ=0
comparing these both equations we get
φ=tan-1(1/5) and t=2 and t2=-sinφ
which is not a feasible solution..
please check the question u have given
If the tangent drawn at a point (t2,2t) on the parabola y2=4x is tha same as the normal drawn at a point(√5cosφ, 2sinφ) in the ellipse 4x2+5y2=20, find the values of t & φ.
-
UP 0 DOWN 0 0 4
4 Answers
39
1u have made a wrong comparison
the correct comparison wud b:-
t/2 = 1/√5tanφ = t2/-sinφ.
That is a1/a2=b1/b2=c1/c2
Understood what mistake u have done??