Past IIT Question

1. A ball moving around the circular path x2+y2-2x-4y-20 = 0 in anticlockwise direction, leaves it tangentially at the point P (-2,-2), after which it rebounds from a a straight wall,and passes through the center of the circle.

Find the eqn. of the straight wall and the line of rebounding of the ball. The perpendicular distance of point P from the wall is 2.5 .

2 Answers

71
Vivek @ Born this Way ·

Reviving this one.

1
pandit ·


the tangent equation is
2x+3y=16

the point (h,k) lies at a distance of (√2*2.5) from the point (-2,-2) ,u can find it using parametric method

i.e

h+2=2.5*√2 313
k+2=-2.5*√2 213

now u can find the equation of rebonding wall by the point slope formula

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