11Slope of the point is = 1/3.
3y + 6 =x -1
3y -x = -7
2x + 6 - x = -7
x + 6 = -7
x = -13
Therefore it will not cut the line segment
prove that the line 2x-3y+6=0 does not cut the line segment joining points (-2,-3) and (1,-2)
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6 Answers
11
1[1]a easy one[1].............isn't it!!!! but a good one i feel
it is not a doubt........but i posted it as i thought it would broaden the outlook of all aspirants before jumping to ans. as in this problem......
following diagram will make everything clear...............(for those who messed this one)
in the above diagram u can easily make out that line won't cut the line segment.....................[1]
11Your line segment that is drawn is wrong
the co-ordinates are (-2,-3) & (1,-2) Therefore it has a slope
1assume that the line cuts the distance between given points in a ratio λ:1 , so the point where the line cuts the straight line joining (-2,-3) and (1,-2) is (α,β)≡ 
since this also lies on the given line, 2α-3β+6=0
subs, and solving for λ, it is found to be negative.
or the given line divides the line joining the 2 points externally
hence proved
1@virang,
dude read the thing i wrote along with that diagram.........
it is just a illustration did u see the coordinates.........i din wrote them...
and even if u r so particular to find out mistake there u can't becoz u can always tranform the axes.............lol[3]