some easy vector problems #4!

VITEEE 2015 Coaching › Co-ordinate Geometry questions › some easy vector problems #4!

Find the lengths of diagonals of the parallelogram constructed on the vectors
p=2a+b and q=a-2b, where a and b are unit vectors and forming an angle of 60Â°.

#Mathematics #Co-ordinate Geometry

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Lokesh Verma ·2009-03-11 22:57:22

the resultant will be p+q

= 3a-b

|3a-b|²= (3a-b).(3a-b) = 9a²+b²-6a.b

length² is 9+1-1/2=10-3=7

length = √7

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Aakash Sharawat ·2009-03-12 07:32:06

there are two values of the diagonals!!!!!!!!
i got one as âˆš7 but the other that i was getting was âˆš5 and this was a single choice correct and the two values that i got were present there but paired up with other values!!!!!!
so what will be the other value?

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Basic Integral Calculus Operators Symbols Matrix Cases

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∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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some easy vector problems #4!

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