ans. ths plzzz

minimum value will be 5

maximum value will be 9

maximum value will be for 2^p

minimum value for 3^q

Why are these last 2 statements correct?

suppose that p+q is smallest for p=a,q=b

p+q is smallest ... so

2^p.3^q is such that 100<2^p.3^q<1000

case 1

2^p.3^q<1000

but 2^p.2^q<2^p.3^q<1000

2^p+q<1000

so the pair(p+q,0) will also work....

same way for 100<2^p.3^q
so 100<2^p.3^q<3^p.3^q = 3^p+q

so the pair (0,p+q) will work as well.

SO for (a,b) satisfying the largest or smallest criterion, it is the same as (a+b,0) and (0,a+b)

Now i guess it is simple to follow and solve :)