stupid question

the expansion is e^x is alway written as
e^x= \frac{1^}{0!}+\frac{x^1}{1!}+\frac{x^2}{2!}+\frac{x^3}{3!}+..........
And not
e^x= \frac{x^0}{0!}+\frac{x^1}{1!}+\frac{x^2}{2!}+\frac{x^3}{3!}+..........

No da x⁰ is always simplified and written as 1 for convinience

anyways, the source is reliable.....i doubt if u cud get a more reliable source than wiki

http://upload.wikimedia.org/math/0/b/c/0bc08045195dc823c22d1fa283cb0759.png

http://www.math.com/tables/expansion/exp.htm

have a look at this 1
the 1st 1 u r making mistake in
and u r confusing between the 1st and the 3 rd 1

hope this could help

i didn't get u mani

see the expansion of e^x is

e^x=\sum_{n=0}^{\infty}{\frac{x^n}{n!}}

so for x=0, why Doesn't that expansion hold good?

Why are dodging the original definition??

e^x= x⁰/0! + x¹/1! +x²/2! + x³/3! + ................

And haven't we learnt that (cos90°).(tan90°)≠1 even though sin90°=1??

even though we can cancel the two cos90°s??[5][5][5][5][5]

bHAI JO PEHLI DEFINITION DI HAI WOH ORIGINAL HAI

PEHLE TU YEH BATA
KI
TU PAANGE LE RAHA HAI
YA
FIR

YEH TERE POTENTIAL OUTSTANDING AND OUT OF THE WORLD BRAIN KI KHOJ HAI[7][7][7]

this defination is for x> 0

:P

arey, what is this??