nice and easy

show that
n! < {(n+1)/2}^2 for n belonging to N

7 Answers

11
Devil ·

I think this is what u intended....
n!<{n+12}^n....

106
Asish Mahapatra ·

If that is the case
then:
n!=(1*n)(2*(n-1))*.....

(1+n)2/4 ≥ 1*n
(2+n-1)2/4 ≥ 2*(n-1)
.
.
.
continuing and multiplying
(n+12)2(n/2) ≥ n!
or n! ≤ (n+12)n

1
rahul1993 Duggal ·

@asish correct solution.
but equality is not valid.
keep trying there's a simpler solution

1
rahul1993 Duggal ·

oh i forgot to mention n>1 asish your solution is perfect

106
Asish Mahapatra ·

yeah equality not valid bcz nos are not equal... :)

11
Devil ·

What abt AM-GM on 1st 'n' naturals?

1
rahul1993 Duggal ·

that's right soumik :D

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