ABCD is a prallelogram. Vertex D meets the side BC when produced to E such that
LDEC = 90° and LDCB = 150°. A person starts from E and reaches C with some
speed in time t seconds and then from C to B and again from C to D and notices
the difference between the length of BC and CD to be 1 m. He againstarts from C
and reaches A with a speed of 2.5m/s in 2s and returns back to C again. The
length of BD given is 1m. Again a tower DR stands on DE and a string is attached to
R and E (assume that there is no sack in it). Q is the mid point of string RE and
LDRE = 300. Then find the length of the string with no sack in it which is attached
to D and Q
[Ans. 1 metre]
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