400000

IIT JEE Preparation › Trignometry questions › 400000

A vertical pole consists of two portions,the lower being 1/3rd of the whole.If the upper portion subtends an angle arctan(1/2) at a point in a horizontal plane through the foot of the plane and distance 40ft from it,then the height of the pole is ________

This sum is easy,but i couldn't understand its geometry !!!!!!!!

#Mathematics #Trignometry

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7 Answers

1

Pavithra Ramamoorthy ·2008-12-20 05:06:46

NO TENSION............

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11

Anirudh Narayanan ·2008-12-20 05:11:49

SEE WHETHER D SKETCH IS RIT......

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62

Lokesh Verma ·2008-12-20 05:13:42

Good work aragon :)

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11

Anirudh Narayanan ·2008-12-20 05:16:54

Thanx Nishant bhaiyyah. How 2 proceed after this?

P.S:
Aragorn please :)

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11

Anirudh Narayanan ·2008-12-20 06:10:22

x/40 = tan[Î¸+arctan(1/2)]

x/120= tanÎ¸

Will you get answer if you solve these equations?

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11

Anirudh Narayanan ·2008-12-20 07:32:29

Answer anyone?

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62

Lokesh Verma ·2008-12-20 11:57:27

x/40 = tan[Î¸+arctan(1/2)]

x/40 = ( tan Î¸ + 1/2 )/ (1-1/2 tan Î¸)

x/120= tanÎ¸

Substitute tan Î¸ above!

x/40 = (x/120 + 1/2) / (1-1/2.x/120)

this is a quadratic in x... just solve it :)

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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