Evaluate this expression

3(sin²x + cos²x -2 cosxsinx)² + 6(sin²x +cox²x + 2cosxsinx)+4 sin⁶+4cos⁶x

= 3(1-2cosxsinx)²+6(1+2cosxsinsx) + 4(sin⁶x + cos⁶x)

= 3(1 + 4 cos²xsin²x -4sinxcosx) +6 + 12cosxsinx + 4(sin⁶x + cos⁶x)

= 3 + 12 cos²xsin²x - 12sinxcosx + 6 + + 12cosxsinx +4(sin⁶x + cos⁶x)

= 9 +12cos²sin²x + 4(sin⁶x + cos⁶x)

(sin²x +cos²x)³ = sin⁶x + cos⁶x + 3cos²xsin²x(sin²x + cos²x)

9 +12cos²sin²x + 4 - 12cos²sin²x
= 13
Which is the final answer

[11][11][11].....[59]...........

Bhaiyya is it rite?

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rite METHOD :

LET sinx = 1
==> cosx = 0;

so 3+6+4 = 13 NOW ITS CRRCT [4] [4]