106yeah u r correct.
Q1. The value of sin-1(2x√1-x2) is
(a) 2sin-1x for all x
(b) 2sin-1x for lxl < 1
(c) Î - 2sin-1x for lxl > 1/√2
(d) none of these
Q2. A/R
Stmnt 1 : If x > 0, y > 0 and x > y, then tan^-^1\frac{x}{y} + tan^-^1\frac{x+y}{x-y}
is 3\pi /4
Stmnt 2 : tan^-^1a + tan^-^1b = \pi + tan^-^1\frac{a+b}{1-ab} if a>0,b>0,ab>1
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5 Answers
1Q2
Statement 1 false
Statement 2 true
x>y => tan-1x/y > pi/4
Clearly x+y > x-y =>tan-1(x+y)/(x-y) >pi/4
Neither is negative, given
so the above two values are less than pi/2
Therefore
the given adds up to pi/2<value<pi
So, it can never be equal to pi/4
Statement2 is true being a basic rule
I will Xplain that if needed
106Edited 2nd question:
A is correct now.
So will it be option A or option B
Please explain first one gordo. if u take a negative value then it is not satisfied