Prove!

Prove

\frac{sin 2A+sin 2B+ sin 2C}{Cos A + Cos B + Cos C-1}=8cos\frac{A}{2}cos\frac{B}{2}cos\frac{C}{2}

This is from IIT JEE 1977

5 Answers

1
skygirl ·

well i am getting [8sinA/2sinB/2sinC/2] ....

1
skygirl ·

bhaiya u sure abt the question ?

1
skygirl ·

no no sorry its okie............

1
Philip Calvert ·

are A B C anlges of a Δ [7]

1
skygirl ·

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