solution of triangles

Q1 In a triangle ABC r1= 2r2= 3r3. Find a:b .

Q2 In an isoceless triangle ABC one of the angle is 120° and radius of incircle is √3.What is the area of the triangle?

plz post the whole solution as im getting wrong answer in both questions

5 Answers

62
Lokesh Verma ·

Δs-a=2Δs-b=3Δs-c

s-a:(s-b)/2:(s-c)/3=k

s-a=k
s-b=2k
s-c=3k

s=6k

a=5k
b=4k
c=3k

1
Che ·

2)sides be a,a,b
area=(1/2)(a)(asin120)=√3/4 a2
a/sin30=b/sin120

s=a+(b/2)

and (raduis of incircle)=area/s

use them...get the ans

1) r1=s.tan(A/2)
r2=s.tan(B/2)
r3=s.tan(C/2)

tan(A/2) :tan(B/2):tan(C/2)=6:3:2

tanA/2=6k

tanB/2=3k

tanC/2=2k

now in triangle ABC

wer A+B+C=180

tanA/2 .tanB/2 +tanB/2 .tanC/2+tanC/2 .tanA/2=1

11
vaibhav sharma ·

thank you very much NISHANT SIR and CHE SIR

1
bindaas ·

CHE SIR

rofl and lmao

bhai we guys are only in college !!

waISe i do have to call my seniors with some gesture every time i meet them nahi to kuch bura hoga

1
Che ·

hahaha......

lol man....vaibhav u dont need to call me sir ...i m of the same age as u r ;)

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