Find the angle at the vertex of an isosceles triangle of max area for the given length 'l' of the median to 1 of its equal sides. Also find the max area.
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1 Answers
1The maximum Area of any isosceles triangle always occurs when the angles are 90°,45°,45°
That is when it is a rt angled triangle.
Therefore angle at the vertex is 90°
Now draw the figure..
If length of equal side is 2x..
THen you will find that by applying Pythagoras theorem You get x=L/√5
And area is 1/2 * (2x)2
Which gives Area = 2L2/5
