1ya ramku.........hw did u get 0??????????
it is sin-1x/a and cos-1√a2-x2/a
1)Tan-1{x/√a2-x2} convert 2 simplest form.
2)sin-1{(sin x +cos x)/√2} ;-Î /4<x<Î /4
3)if a>b>>c>0,prove that cot-1(ab+1/a-b) + cot-1(bc+1/b-c) + cot-1(ca+1/c-a)= Î
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8 Answers
62Hints/ Questions to ask to urself..
1) Draw a triangle with perpendicular x and base √a2+x2
2) (sin x + cos x) / √2 = sin(x+Ï€/4)
Check if x+pi/4 lies in the principal range for sin inverse!
3) what is the principal range for cot-1
does the condition a>b>c make a difference to it!
62no!
see the hypotenuse will become |a|
draw the triangle
then u will have sin-1(x/|a|)
1
1hey sorryy ... sorry... sorry.... silly mistake.......... dats y got wrong......dis d prob wit me.. i use ma extraordinary brain n get it wrong...
623rd one i think u will need to convert cot inverse to tan invers
then see if the sum of tan inverse give you something!!!
That is all
and then there will be som constants.. (That is what i was referring to!)
like due to shifting from the principal value
one term will not satisfy (x>y) for tan-1(x - y)
That is all that i meant!
